Question

.... Помогите Срочно!!!!!!

Answer 1

Ответ:

$1.1)\ \ kx+3y+3x+ky=(kx+ky)+(3x+3y)=k(x+y)+3(x+y)=\\\\=(x+y)(k+3)\\\\1.2)\ \ a^6-6a^4-3a^2+18=(a^6-6a^4)+(-3a^2+18)=\\\\=a^4\, (a^2-6)-3\, (a^2-6)=(a^2-6)(a^4-3)$

$2.1)\ \ 2x\cdot (a^2-3)+(a^2-3)=(a^2-3)(2x+1)\\\\2.1)\ \ 5(3a-b)-6x(b-3a)=(3a-b)(5+6x)$

$3)\ \ 3(2x+3)-2(3x+5)=x-2\\\\6x+9-6x-10=x-2\\\\-1=x-2\\\\-1+2=x\\\\x=1$