Question

Помогите с алгеброй 10 класс

Answer 1

в)

$-\sqrt{3} tg(\pi - x) = 1$

$\sqrt{3}tg(x) = 1$

$tg(x) = \frac{\sqrt{3}}{3}$

$x = arctg(\frac{\sqrt{3} }{3}) + \pi k$

$x = \frac{\pi}{6} + \pi k$

г)

$ctg(2 \pi - x) + tg (\frac{3 \pi}{2} + x ) = 2$

$-2ctg(x)= 2$

$ctg(x) = -1$

$x = \frac{3 \pi}{4} + \pi k$