Question

Виконайте усно
√293............

Answer 1

Ответ:

а)cos²Alfa

б)sin²alfa

в)sin²alfa

г)-5sin²beta

Answer 2

Ответ:

1) $1-sin^{2} \alpha$=$cos^{2} \alpha$

2) $1-cos^{2} \alpha$=$sin^{2} \alpha$

3) $tg^{2} \alpha *cos^{2} \alpha$=$(tg\alpha *cos\alpha )^{2} =(\frac{sin\alpha }{cos\alpha } *cos\alpha )^{2} =sin^{2}\alpha$

4) $5cos^{2} \beta - 5=-5(-cos^{2} \beta +1)=-5sin^{2} \beta$