Question

log [2]  (9-x)= 3-x вычислить

Answer 1

Log [2](9-x)= 3-x
Log [2](9-x)=Log [2](3-х)^2
9-x=(3-x)^2
9-x=9-6x+x^2
-x^2+5x=0
x(-x+5)=0
x=0 , x=5