Question

решите уравнение
2cos^2x=1+sinx

Answer 1

2-2sin^2 x-2-sin x=0
-2sin^2 x-sin x=0
2sin^2 x+sin x=0
sin x(2sin x+1)=0
sin x=0 x=pi/2+2pin
2sin x+1=0
sin x=-1/2
x=-pi/6+pin