Question

x2(2-в степени) -2xc+2cy-xy
2az-z2(2-встепени)-bz+2ab
x2(2-в степени) -2y+x-2xy

Answer 1

Ответ:

${x}^{2} - 2xc + 2cy - xy = x \times (x - 2c) - y(x - 2c) = (x - 2c)(x - y) \\ 2az - {z}^{2} - bz + 2ab = z(2a - z) + b(2a - z) = (2a - z)(z + b) \\ {x}^{2} - 2y + x - 2xy = x(x + 1) - 2y(1 + x) = (x + 1)(x - 2y)$