Question

Срочно
$\sqrt{2} \sin( \frac{\pi}{12} - 3x ) - 1 = 0$
​

Answer 1

√2*sin(П/12-3х)-1=0

√2*sin(П/12-3х)=1

√2*sin(3x-П/12)=-1

Делим обе части на √2:

sin(3x-П/12)=–1/√2

sin(3x-П/12)=–√2/2

3х-П/12 = (-1)ⁿ * arcsin(–√2/2) + 2Пn; n∈Z

3x-П/12 = (-1)^(n+1) * arcsin(√2/2) + 2Пn; n∈Z

3x-П/12 = (-1)^(n+1) * П/4 + 2Пn; n∈Z

3x = (-1)^(n+1) * П/4 + П/12 + 2Пn; n∈Z

x = (-1)^(n+1) * П/12 + П/36 + (2/3)Пn; n∈Z