Question

Реши квадратное уравнение 2x^2−5x+2=0.

Answer 1

2x² - 5x + 2 = 0

2x² - x - 4x + 2 = 0

x × (2x - 1) - 2 × (2x - 1) = 0

(2x - 1) × (x - 2) = 0

2x - 1 = 0

x - 2 = 0

x¹ = 1/2

x² = 2

Answer 2

$2x^{2} -5x+2=0$

$a=2; b=-5; c=2$

$D=b^{2} -4ac=(-5)^{2} - 4*2*2=25-16=9$

$x_{1} =\frac{-b+\sqrt{D} }{2a} = \frac{5+\sqrt{9} }{4} = 2$

$x_{2} =\frac{-b-\sqrt{D} }{2a} = \frac{5-\sqrt{9} }{4} = \frac{2}{4} = \frac{1}{2} = 0.5$

Ответ: 0,5; 2