Question

помогите пожалуйста!!

Answer 1

Ответ:

(2,5 ; 0,5)

Решение:

$\left \{ {{x^2-y^2=6} \atop {x-y=2}} \right. \left \{ {{x^2-y^2=6} \atop {y=x-2}} \right. \left \{ {{x^2-(x-2)^2=6} \atop {y=x-2}} \right. \left \{ {{x^2-(x^2-2*2x+4)=6} \atop {y=x-2}} \right. \left \{ {{x^2-x^2+4x-4)\=6} \atop {y=x-2}} \right. \\\\ \left \{ {{4x=6+4} \atop {y=x-2}} \right. \left \{ {{x=10:4} \atop {y=x-2}} \right. \left \{ {{x=2,5} \atop {y=2,5-2}} \right. \left \{ {{x=2,5} \atop {y=0,5}} \right.$