Question

42²+18²+4³-32²+Х-$\sqrt{400}$=???

Answer 1

Ответ:

$42 {}^{2} + 18 {}^{2} + 4 {}^{3} - 32 {}^{2} + x - \sqrt{4 00 } \\ = \\ (42 - 32) \times (42 + 32) + 324 + 64 + x - 20 \\ = \\ 10 \times 74 + 324 + 64 + x - 20 \\ = \\ 740 + 324 + 64 + x - 20 \\ = \\ 1108 + x$