Question

найти производную dy/dx
функции y = sin ln(x³+ 1) ​​

Answer 1

Ответ:

$y = \sin( ln( {x}^{3} + 1 ) )$

$y' = \cos( ln( {x}^{3} + 1 ) ) \times ( ln( {x}^{3} + 1)) ' \times ( {x}^{3} + 1) '= \\ = \cos( ln( {x}^{3} + 1) ) \times \frac{1}{ {x}^{3} + 1 } \times 3 {x}^{2} = \\ = \frac{3 {x}^{2} }{ {x}^{3} + 1 } \cos( ln( {x}^{3} + 1) )$