Question

$(1 + \tan( { \alpha }^{2} ) \times \cos( { \alpha }^{2} ) - 1$
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Answer 1

$1 + \frac{1}{ {tg}^{2} \alpha } = \frac{1}{ { \cos }^{2} \alpha }$

$( \frac{1}{ \cos^{2} \alpha } \times\cos^{2} \alpha ) - 1 = 1 - 1 = 0$