Question

Пж выполните действие​

Answer 1

$\frac{4}{3a+2b}-\frac{2}{2b-3a}+\frac{8b}{4b^{2}-9a^{2}}=\frac{4}{3a+2b}-\frac{2}{2b-3a}+\frac{8b}{(2b-3a)(2b+3a)}=\frac{4(2b-3a)-2(2b+3a)+8b}{(2b-3a)(2b+3a)}=\\\\=\frac{8b-12a-4b-6a+8b}{(2b-3a)(2b+3a)}=\frac{12b-18a}{(2b-3a)(2b+3a)}=\frac{6(2b-3a)}{(2b-3a)(2b+3a)}=\boxed{\frac{6}{2b+3a}}$