Question

Возведите в квадрат
1) (4а+1/4в)
2) (0.4-в)
3) (24а - 0.3в)
4) (-3к+0.1с)​

Answer 1

$(4a + \frac{1}{4} b) {}^{2} \\( 4a) {}^{2} + 2 \times 4a \times \frac{1}{4} b + ( \frac{1}{4} b) {}^{2} \\ 16a {}^{2} + 2ab + \frac{1}{16} b {}^{2}$

$(0.4 - b) {}^{2} \\ ( \frac{2}{5} - b) {}^{2} \\ \frac{4}{25} - \frac{4}{5} b + b {}^{2}$

$(24a - 0.3b) {}^{2} \\ (24a - \frac{3}{10} b) {}^{2} \\ 576a {}^{2} - \frac{72}{5} ab + \frac{9}{100} b {}^{2}$

$( - 3k + 0.1c) {}^{2} \\ ( - 3k + \frac{1}{10} c ) = ( \frac{1}{10}c - 3k) {}^{2} \\ \frac{1}{100} c {}^{2} - \frac{3}{5} ck + 9k {}^{2}$