Question

подайте у вигляде кврадрате двухчлена
1) 16 + 8c + c^2
2) 25a^4 – 10a^2 d^3 + d^6
3) 36a^2 – 24ab + 4b^2
4) 0.01m^2 + 2mc + 100c^2
5) 36c^2 + 9d^2 + 36cd
6) 9x^2 + 1 – 6x
7)12с + 9с^2 + 4

Answer 1

Ответ:

$16 + 8c + {c}^{2} = {(4 + c)}^{2}$

$25 {a}^{4} - 10 {a}^{2} {d}^{3} + {d}^{6} = {(5 {a}^{2} - {d}^{3}) }^{2}$

$36 {a}^{2} - 24ab + 4 {b}^{2} = {(6a - 2b)}^{2}$

$0.01 {m}^{2} + 2mc + 100 {c}^{2} = {(0.1m +10c) }^{2}$

$36 {c}^{2} + 9 {d}^{2} + 36cd = {(6c + 3d)}^{2}$

$9 {x}^{2} + 1 - 6x = {(3x - 1)}^{2}$

$12c + 9 {c}^{2} + 4 = {(2 + 3c)}^{2}$