Question

5x^2-22x-48=0 способом коэффициэнтов

Answer 1

$5x^2 - 22x - 48 = 0$

домножим уравнение на 5

$5^2\cdot x^2 - 22\cdot 5\cdot x - 240 = 0$

$(5x)^2 - 22\cdot(5x) - 240 = 0$

$y = 5x$

$y^2 - 22y - 240 = 0$

$y_1 + y_2 = 22$

$y_1\cdot y_2 = -240$

$y_1 = 30$

$y_2 = -8$

$x = \frac{y}{5}$

$x_1 = \frac{30}{5} = 6$

$x_2 = \frac{-8}{5} = -\frac{16}{10} = -1{,}6$