Question

Решите алгебру №336 №340.Даю 35 баллов.Спс))) мне срочно надо

Answer 1

$1)\ a^2+2ac+c^2=(a+c)^2\ 2)\ m^2-2mn+n^2=(m-n)^2\ 3)\ x^2-4xy+4y^2=(x-2y)^2\ 4)\ a^2+2ca+c^2=(a+c)^2\ 5)\ c^2+14c+49=(c+7)^2\ 6)\ k^2-6k+9=(k-3)^2$
$31^2=(30+1)^2=30^2+60+1 = 961\ 51^2=(50+1)^2=50^2+100+1=2601\ 39^2=(30+9)^2=30^2+18*30+9^2=1521\ 103^2=(100+3)^2=100^2+6*100+3^2=10609\ 99^2=(90+9)^2=90^2+18*90+9^2=9801\ 999^2=(900+99)^2=900^2+2*99*900+99^2=998001\ 1001^2=(1000+1)^2=1000^2+2000+1=1002001\ 105^2=(100+5)^2=100^2+10*100+5^2=11025\ 52^2=(50+2)^2=50^2+4*50+2^2=2704$

Answer 2

ипиши без [tex] ,/////

Answer 3

a 336 NOMER