Question

Найти производные функций.

y = 2/sinx

y = -6 ctg x

y = tgx/3

Answer 1

Ответ:

$1)y = \frac{2}{ \sin(x) } = 2 {( \sin(x)) }^{ - 1}$

$y' = - 2 {( \sin(x)) }^{ - 2} = - \frac{2}{ { \sin}^{2} (x)}$

$2)y = - 6ctg(x)$

$y '= - 6 \times ( - \frac{1}{ { \sin }^{2} (x)} ) = \frac{6}{ { \sin}^{2}(x) }$

$2)y = \frac{1}{3} tg(x)$

$y' = \frac{1}{3 { \cos }^{2}(x) }$