Question

Решить уравнение
$(x-1)^{4}-x^{2}+2x-73=0$
Решается вроде заменой, но возникли некоторые сложности

Answer 1

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Answer 2

$(x-1)^4 - x^2 + 2x - 73 = 0\\\\(x-1)^4 - (x^2 - 2x + 1) - 72 = 0\\\\(x-1)^4 - (x-1)^2 - 72 = 0\\\\\\t = (x-1)^2\\\\t^2 - t - 72=0\\\\D = 1 + 4\cdot72 = 289\\\\t_1 = \dfrac{1-17}{2} = -8\\\\t_2 = \dfrac{1+17}{2} = 9\\\\\\(x-1)^2 = -8\\\\x \in \varnothing\\\\\\\\(x-1)^2 = 9\\\\x-1 = \pm3\\\\x_{1,2} = 1 \pm 3\\\\\\\\x_1 = -2, \; x_2 = 4$