Question

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Преобразовать корни

Answer 1

$(\sqrt{3\frac{6}{7} } -\sqrt{1\frac{5}{7}}):\sqrt{\frac{3}{28}} =(\sqrt{\frac{27}{7} }-\sqrt{\frac{12}{7}})*\sqrt{\frac{28}{3}} =\sqrt{\frac{27}{7}}*\sqrt{\frac{28}{3}}-\sqrt{\frac{12}{7}}*\sqrt{\frac{28}{3}}=\\\\=\sqrt{\frac{27*28}{7*3} } -\sqrt{\frac{12*28}{7*3}}=\sqrt{36}-\sqrt{16}=6-4=\boxed2$

Answer 2

Ответ:

$\Big(\sqrt{3\dfrac{6}{7}}-\sqrt{1\dfrac{5}{7}}\Big):\sqrt{\dfrac{3}{28}}=\Big(\, \sqrt{\dfrac{27}{7}}-\sqrt{\dfrac{12}{7}}\ \Big)\cdot \sqrt{\dfrac{28}{3}}=\sqrt{\dfrac{27\cdot 28}{21}}-\sqrt{\dfrac{12\cdot 28}{21}}=\\\\\\=\sqrt{36}-\sqrt{16}=6-4=2$