Question

8 задание пожалуйста даю 100 баллов​

Answer 1

Ответ:

Объяснение:

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Answer 2

$ODZ:\\\\\left[\begin{array}{ccc}x+1>0\\x+19>0\end{array}\right\\\\\\\left[\begin{array}{ccc}x>-1\\x>-19\end{array}\right \ \Rightarrow x>-1 \\\\a_{1}=log_{2}3\\\\a_{2}=log_{2}(x+1)\\\\a_{3}=log_{2}(x+19)\\\\a_{2}=\frac{a_{1}+a_{3}}{2}\\\\a_{1}+a_{3}=2a^{2} \\\\log_{2}3+log_{2}(x+19)=2log_{2}(x+1)\\\\log_{2}[3(x+19)]=log_{2}(x+1)^{2}\\\\3(x+19)=(x+1)^{2} \\\\3x+57=x^{2} +2x+1\\\\x^{2}-x-56=0\\\\x_{1} =8\\\\x_{2}=-7- \ teorema \ Vieta\\\\Otvet:\boxed{x=8}$