Question

Найти неопределенный интеграл
$\frac{x^5}{x^{12}-1}$

Answer 1

Ответ:

$\int \dfrac{x^5}{x^{12}-1}\, dx=\int \dfrac{x^5}{(x^{6})^2-1}\, dx=\dfrac{1}{6}\int \dfrac{6x^5\, dx}{(x^{6})^2-1}=\Big[\ t=x^6\ ,\ dt=6x^5\, dx\ \Big]=\\\\\\=\dfrac{1}{6} \int \dfrac{dt}{t^2-1}=\dfrac{1}{6}\cdot \dfrac{1}{2}\cdot ln\Big|\dfrac{t-1}{t+1}\Big|+C=\dfrac{1}{12}\cdot ln\Big|\dfrac{x^6-1}{x^6+1}\Big|+C$