Question

Продифференцировать функции ​

Answer 1

Ответ:

формула:

$y' = ( ln(y)) ' \times y$

$( ln(y))' = ( ln( {( \sin(8x - 7)) }^{cth(x + 3)} ) '= \\ = (cth(x + 3) \times ln( \sin(8x - 7)) ) '= \\ = - \frac{1}{ {sh}^{2} (x + 3)} ln( \sin(8x - 7) ) + \frac{1}{ \sin(8x - 7) } \cos(8x - 7) \times 8 \times cth(x + 3) = \\ = - \frac{ ln( \sin(8x - 7) ) }{ {sh}^{2}(x + 3) } + 8cth(x + 3) \times ctg(8x - 7)$

$y '= {( \sin(8x - 7)) }^{cth(x + 3)} \times ( - \frac{ ln( \sin(8x - 7) ) }{ {sh}^{2}(x + 3) } + 8cth(x + 3) \times ctg(8x - 7))$