Question

Продифференцировать функции​

Answer 1

Ответ:

$y' = \frac{U'V - V'U}{ {V}^{2} } = \\ = \frac{ \frac{1}{ ln(7) \times (2 {x}^{2} + 5)} \times 4x {(x - 4)}^{2} - 2(x - 4) log_{7}(2 {x}^{2} + 5) }{ {(x - 4)}^{4} } = \\ = \frac{(x - 4)( \frac{4x(x - 4)}{ ln(7) \times (2 {x}^{2} + 5)} - 2 log_{7}(2 {x}^{2} + 5 ) }{ {(x - 4)}^{4} } = \\ = \frac{1}{ {(x - 4)}^{3} } \times ( \frac{4x(x - 4)}{ ln(7) \times (2 {x}^{2} + 5)} - 2 log_{7}(2 {x}^{2} + 5 ) )$