Question

НУЖНО ВЫЧИСЛИТЬ! СРОЧНО ПОМОГИТЕ!!!!!

Answer 1

Ответ:

Пошаговое объяснение:

sin(π/6+π/4) = sin(π/6)*cos(π/4) + cos(π/6)*sin(π/4) =

= 1/2 * √2/2 + √3/2 *√2/2 = (√2+√6)/4

cos(π/6+π/4) = cos(π/6)*cos(π/4) - sin(π/6)*sin(π/4) =

=√3/2 * √2/2 - 1/2 * √2/2 = (√6 - √2)/4

tg(π/6+π/4) = (tg(π/6)+tg(π/4))/(1-tg(π/6)*tg(π/4))

(tg(π/6)+tg(π/4)=√3/3 +1 =(3+√3)/3

1-tg(π/6)*tg(π/4) = 1-√3/3 * 1 = (3-√3)/3

tg(π/6+π/4) = (3+√3)/(3-√3)

ctg(π/6+π/4) =( ctg(π/6)*ctg(π/4) -1) / (ctg(π/6)+ctg(π/4) )

ctg(π/6)*ctg(π/4) -1 = √3 * 1 -1 = √3 -1

ctg(π/6)+ctg(π/4) = √3 +1

ctg(π/6+π/4) = (√3 -1) /(√3 +1)