Question

Вычислите неопределенный интеграл ​

Answer 1

$\int x^3\cdot(1-6x^2)\,dx =\int x^3-6x^5\, dx=\\\\\\=\int x^3\,dx-\int6x^5\,dx=\boxed{\dfrac{x^4}{4}-x^6+C}$