Question

Продифференцировать функции​

Answer 1

Ответ:

$y' = \frac{ {e}^{ctg5x} \times ( - \frac{1}{ { \sin }^{2}(5x) } ) \times 5 \times {(3x - 5)}^{4} - 4 {(3x - 5)}^{3} \times 3 \times {e}^{ctg5x} }{ {(3x - 5)}^{8} } = \\ = \frac{ {e}^{ctg5x} {(3x - 5)}^{3}( - \frac{5(3x - 5)}{ { \sin }^{2} (5x)} - 12) }{ {(3x - 5)}^{8} } = \\ = - \frac{ {e}^{ctg5x}( \frac{15x - 25}{ { \sin}^{2}(5x) } - 12)}{ {(3x - 5)}^{5} } = \\ = - \frac{ {e}^{ctg5x} }{ {(3x - 5)}^{5} } \times ( \frac{15x - 25}{ { \sin }^{2}(5x) } - 12)$