Question

$\frac{3c {}^{ - 1} }{a {}^{3} } \div ( \frac{9c {}^{ - 3} }{a {}^{4} } ) =$
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Answer 1

$\dfrac{3c^{-1}}{a^3}:\left(\dfrac{9c^{-3}}{a^{4}}\right)=\dfrac{3c^{-1}}{a^3}\cdot\dfrac{a^{4}}{9c^{-3}}=\dfrac{3c^{-1}a^4}{a^3\cdot9c^{-3}}=\dfrac{ac^2}{3}=\dfrac{1}{3}ac^2$