Question

розкласти на множники
12x+38y
x³+x
8a(b-3)+c(b-3)
7x+7y+ax+ay
​

Answer 1

1. 2(6x+19y)
2. x(x2+1)
3. (8a+c)•(b-3)
4. 7(x+y)+a(x+y)=(7+a)•(x+y)

Answer 2

1. 12x+38y=12(x+4y)

2.x^3+x=x(x^2+1)

3.8a(b-3)+c(b-3)=(8a+c)(b-3)

4. 7x+7y+ax+ay=(7x+ax)+(7y+ay)=x(7+a)+y(7+a)=(x+y)(7+a)