Предмет: Химия, автор: farida6978

В две пробирки налейте по 1-2 мл раствора серной кислоты. В одну пробирку поместите гранулу цинка, в другую- кусочек медной проволоки или стружки. Что наблюдаете? Объясните результат Напишите уравнения реакций в молекулярной и ионной формах. Рассмотрите окислительно-восстановительные процессы. СРОЧНО НУЖНО

Ответы

Автор ответа: lapovanastya

Ответ:

в пробирке с Zn будет выделяться водород , с медью мы не увидем никаких изменений

zn + h2so4 = znso4 + h2

cu + h2so4 не идет

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