Question

решить неравенство 2х^2-2х>12​

Answer 1

$2x {}^{2} - 2x - 12 > 0$

$x {}^{2} - x - 6 > 0$

$x {}^{2} + 2x - 3x - 6 > 0$

$x \times (x + 2) - 3(x + 2) > 0$

$(x + 2)(x - 3) > 0$

$x + 2 > 0 \\ x - 3 > 0$

$x + 2 < 0 \\ x - 3 < 0$

$x > - 2 \\ x > 3$

$x < - 2 \\ x < 3$

$x = < - \infty . - 2 > < 3. + \infty >$