Question

ПОМОГИТЕ ПОЖАЙЛУСТА!!!!

Answer 1

$\frac{3x(2-x)^{-1}}{1-(\frac{2-x}{3x})^{-1}}=\frac{3x*\frac{1}{2-x}}{1-\frac{3x}{2-x} }=\frac{\frac{3x}{2-x} }{\frac{2-x-3x}{2-x}}=\frac{3x*(2-x)}{(2-x)*(2-4x)}=\frac{3x}{2(1-2x)}\\\\x=0,6\\\\\frac{3*0,6}{2*(1-2*0,6)}=\frac{1,8}{2*(1-1,2)}=\frac{0,9}{-0,2}=-4,5\\\\Otvet:\boxed{-4,5}$