Question

РЕшите пожалуйста очень надо

Answer 1

Ответ:

$y = 7( {4 {x}^{2} - 4x + 4)}^{7} \\ \\ у' = 7 \times 7( {4 {x}^{2} - 4x + 4})^{7 - 1} \times \\ \times ( {4 {x}^{2} - 4x + 4})' = \\ = 49(8x - 4)({4 {x}^{2} - 4x + 4})^{6} = \\ = (392x - 196)( {4 {x}^{2} - 4x + 4})^{6}$

$y = 5 \sqrt{1 + 2 {x}^{3} - {x}^{2} } \\ \\ у' = \frac{5 \times (1 + 2 {x}^{3} - {x}^{2})'}{2\sqrt{1 + 2 {x}^{3} - {x}^{2}} } = \\ = \frac{5(6 {x}^{2} - 2x )}{2\sqrt{1 + 2 {x}^{3} - {x}^{92}}} = \\ = \frac{5 \times 2(3 {x}^{2} - x) }{2\sqrt{1 + 2 {x}^{3} - {x}^{2}}} = \\ = \frac{15 {x - 5x}^{2} }{\sqrt{1 + 2 {x}^{3} - {x}^{2}}}$