Question

решите уравнение: 4c^2+|c|-3=0.
Помогите пожалуиста!У меня СОЧ,даю 35 балов!!!​

Answer 1

Ответ:

$4 {c}^{2} + c - 3 = 0 \\ 1) \\4 {c}^{2} + c - 3 = 0. \: \: \: x \geqslant 0 \\ \\ d = 1 - 4 \times 4 \times ( - 3) = 1 + 48 = 49 = {7}^{2} \\ x1 = \frac{ - 1 + 7}{8} = \frac{6}{8} = \frac{3}{4} \\ x2 = \frac{ - 1 - 7}{8} = - \frac{8}{8} = - 1 \\ 2) \\ 4 {c}^{2} + ( - c) - 3 = 0. \: \: \: x < 0 \\ 4 {c}^{2} - c - 3 = 0 \\ d = 1 - 4 \times 4 \times ( - 3) = 1 + 48 = 49 = {7}^{2} \\ x1 = \frac{1 + 7}{8} = \frac{8}{8} = 1 \\ x2 = \frac{1 - 7}{8} = - \frac{6}{8} = - \frac{3}{2} \\ \\ x1 = - 1 \\ x2 = - \frac{3}{4} \\ x3 = \frac{3}{4} \\ x4 = 1$