Question

ДАМ 100 БАЛЛОВ ПОМОГИТЕ СКОРЕЙ

Answer 1

Ответ:

$1)\ \ y=x^2-3x+4\ \ ,\ \ \ x\in D(y)=R\\\\2)\ \ y=\dfrac{6}{x-2}\ \ ,\ \ \ x-2\ne 0\ \ ,\ \ x\ne 2\ \ ,x\in D(y)=(-\infty ;2)\cup (2;+\infty )\\\\3)\ \ y=\dfrac{5}{x^2+2}\ \ ,\ \ \ x\in D(y)=R\\\\4)\ \ y=\dfrac{7x^2}{x(x+4)}\ \ ,\ \ \ x\ne 0\ \ i\ \ x\ne -4\ ,\ x\in D(y)=(-\infty ;-4)\cup(-4;0)\cup (0;+\infty )\\\\5)\ \ y=\dfrac{3}{x^2+9}\ \ ,\ \ \ x\in D(y)=R$

$6)\ \ y=\dfrac{5}{x(x-3)}\ \ ,\ \ x\ne 0\ ,\ x\ne 3\ ,\ \ x\in D(y)=(-\infty ;0)\cup (0;3)\cup (3;+\infty )\\\\7)\ \ y=\dfrac{x-2}{3x^2-x+10}\ \ ,\ \ 3x^2-x+10>0\ ,\ tak\ kak\ D=-110<0\ ,\\\\x\in D(y)=R\\\\\\\star \ \ R=(-\infty ;+\infty )\ \ \star$