Question

$\frac{ {b}^{8} \times {b}^{ - 4} }{ {b}^{2} }$
ToT​

Answer 1

Ответ:

b⁸ × b^-4 / b²

= b^ (8 + (-4)/b²

= b⁴/b²

= b^(4 - 2)

= b²