Question

3е задание. Срочно, помогите пожалуйста

Answer 1

Ответ:

1.

$f'(x) = 6x + 5 {x}^{ - 2} + 4 \times \frac{1}{2} {x}^{ - \frac{1}{2} } + 0 = \\ = 6x + \frac{5}{ {x}^{2} } + \frac{2}{ \sqrt{x} } \\ f'(1) = 6 + 5 + 2 = 13$

2.

$f'(x) = ln(2) \times {2}^{x} \times \cos(x) - \sin(x) \times {2}^{x} = \\ = {2}^{x} (ln(2) \times \cos(x) - \sin(x)) \\ f'(0) = {2}^{0} ( ln(2) \times \cos(0) - \sin(0) ) = \\ = 1 \times ( ln(2) - 0) = ln(2)$

3.

$f'(x) = \frac{2x(x - 1) - ( {x}^{2} + 2) }{ {(x - 1)}^{2} } = \\ = \frac{2 {x}^{2} - 2x - {x}^{2} - 2}{ {(x - 1)}^{2} } = \\ = \frac{ {x}^{2} - 2x - 2 }{ {(x - 1)}^{2} }$

$f'(2) = \frac{4 - 4 - 2}{1} = - 2$