Question

$log_{5}(7 - x) = log_{5}( 3 - x) + 1$
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Answer 1

log5 (7-x) = log5 (3-x) + 1

log5 (7-x) = log5 (3-x) + log5 (5)

log5 (7-x) = log5 (15-5x)

7-x = 15-5x

4x=8

x=2

Ответ: 2