Question

Помогите!!!!!!!!!!!!!!!!!
 

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Answer 1

Ответ:

$(7x - 12) ^{2} - 4(7x - 12) + 3 = 0 \\ {(7x - 12)}^{2} - (7x - 12) - 3(7x - 12) + 3 =0 \\ (7x - 12)(7x - 12 - 1) - 3(7x - 12 - 1) = 0 \\ (7x - 12 - 1)(7x - 12 - 3) = 0 \\ (7x - 13)(7x - 15) = 0 \\ 1) \\ 7x - 13 = 0 \\ 7x = 13 \\ x = \frac{13}{7} \\ 2) \\ 7x - 15 = 0 \\ 7x = 15 \\ x = \frac{15}{7} \\ x1 = \frac{13}{7} \\ x2 = \frac{15}{7}$