Question

решить уравнения √x²-36=√2x-1





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Answer 1

$\sqrt{x^{2}-36 }=\sqrt{2x-1}\\\\\left \{ {{x^{2}-36=2x-1 } \atop {2x-1\geq0 }} \right.\\\\\\\left \{ {{x^{2}-2x-35=0 } \atop {x\geq0,5 }} \right.\\\\\\\left \{ {{\left[\begin{array}{ccc}x_{1}=7 \\x_{2}=-5-neyd \end{array}\right } \atop {x\geq0,5}} \right.\\\\Otvet:\boxed7$