Question

Посчитайте f'(0), при:​

Answer 1

Ответ:

$a )f'(x) = 2x \cos(x) - \sin(x) \times {x}^{2}$

$f'(0) = 0 - 0 = 0$

$d)f'(x) \frac{ \cos(x) \times (1 - 5x) - \sin(x) \times ( - 5)}{ {(1 - 5 {)}^{2} }^{2} } = \\ = \frac{(1 - 5x) \cos(x) + 5 \sin(x) }{ {(1 - 5x)}^{2} }$

$f'(0) = \frac{1 \times \cos(0) + 5 \sin(0) }{1} = 1 + 0 = 1$