Question

4sin^4x+sin^2 x=0помогите пж​

Answer 1

Ответ:

$4 { \sin(x) }^{4} + { \sin(x) }^{2} = 0 \\ { \sin(x) }^{2} (4 { \sin(x) }^{2} + 1) = 0 \\ { \sin(x) }^{2} = 0 \\ x = \pi \: n \\ 4 { \sin(x) }^{2} + 1 = 0 \\ { \sin(x) }^{2} = - \frac{1}{4} \\ \sin(x) = otveta \: net \\ x = \pi \: n$