Question

(b^3-b^2)(b^3+b^2)-(1+b^2)(1-b^2+b^4)
b=0,1

Answer 1

Ответ:

-1,0001

Объяснение:

(b^3-b^2)(b^3+b^2)-(1+b^2)(1-b^2+b^4) = (b^3)^2 - (b^2)^2

- (1^3 + (b^2)^3) = b^6 - b^4 - 1 - b^6 = - b^4 - 1.

Если b=0,1, то

- 0,1^4 - 1 = - 0,0001 - 1 = -1,0001.