Question

помогите с этой функцией​

Answer 1

Ответ:

$\left\{\begin{array}{l}y=x^2-4\\y-1=2x\end{array}\right\ \ \left\{\begin{array}{l}y=x^2-4\\y=2x+1\end{array}\right\ \ \left\{\begin{array}{l}x^2-4=2x+1\\y=2x+1\end{array}\right\ \ \left\{\begin{array}{l}x^2-2x-5=0\\y=2x+1\end{array}\right$

$\left\{\begin{array}{l}x_1=1-\sqrt6\\y_1=2(1-\sqrt6)+1\end{array}\right\ \ \left\{\begin{array}{l}x_2=1+\sqrt6\\y_2=2(1+\sqrt6)+1\end{array}\right\\\\\\\left\{\begin{array}{l}x_1=1-\sqrt6\\y_1=3-2\sqrt6\end{array}\right\ \ \left\{\begin{array}{l}x_2=1+\sqrt6\\y_2=3+2\sqrt6\end{array}\right$

$\star \ \ \ x^2-2x-5=0\ \ ,\ \ D/4=1+5=6\ \ ,\ \ x_{1,2}=1\pm \sqrt6\\\\\\Otvet:\ \ (1-\sqrt6\ ;\, 3-2\sqrt6\ )\ ,\ \ (1+\sqrt6\ ;\, 3+2\sqrt6\ )\ .$