Question

Даю 50 баллов помогите пожалуйстаста ✔️

Answer 1

Объяснение:

1)

$\frac{ {x}^{2} }{x - 2} = \frac{x}{x - 2} \\ {x}^{2} = x \\ {x}^{2} - x = 0 \\ x \times (x - 1) = 0 \\ x = 0 \\ x = 1$

2)

$\frac{ {y}^{2} - 6y }{y - 5} = \frac{5}{5 - y} \\ ( {y}^{2} - 6y) \times (5 - y) = 5(y - 5) \\ {5y}^{2} - {y}^{3} - 30y \times {6y}^{2} - 5y + 25 = 0 \\ {11y}^{2} - {y}^{3} - 35y + 25 = 0 \\ { - y}^{3} + {11y}^{2} - 10y - 25y + 25 = 0 \\ { - y}^{2} \times (y - 1) + 10y \times (y - 1) - 25(y - 1) = 0 \\ - (y - 1) \times ( {y}^{2} - 10y + 25) = 0 \\ (y - 1) \times ( {y - 5)}^{2} = 0 \\ y - 1 = 0 \\ {(y - 5)}^{2} = 0 \\ y = 1$

1)

$\frac{x + 1}{6} + \frac{20}{x - 1} = 4 \\ \frac{x + 1}{6} + \frac{20}{x - 1} - 4 = 0 \\ \frac{ {x}^{2} - 1 + 120 - 24x + 24}{6(x - 1)} = 0 \\ {x}^{2} + 143 - 24x = 0 \\ {x}^{2} - 24x + 143 = 0 \\ {x}^{2} - 11x - 13x + 143 = 0 \\ (x - 11) \times (x - 13) = 0 \\ x = 11 \\ x = 13$