Question

ДАМ 40 БАЛОВ !!!
8 Номер

Answer 1

$\frac{3x^{2}-3 }{3x+1}=x-2 \\\\\frac{3x^{2}-3 }{3x+1}-x+2=0\\\\\frac{3x^{2}-3-3x^{2}-x+6x+2}{3x+1}=0\\\\\frac{5x-1}{3x+1}=0\\\\\left \{ {{5x-1=0} \atop {3x+1\neq0 }} \right. \\\\\left \{ {{5x=1} \atop {3x\neq-1 }} \right.\\\\\left \{ {{x=0,2} \atop {x\neq-\frac{1}{3}}} \right.\\\\Otvet:\boxed{0,2}$