Question

решите уравнение номер 10.7 (2)​

Answer 1

Ответ:

6

Объяснение:

1. ОДЗ:$\left \{ {x{\neq 3}\atop {x\neq -3}} \right.$
2. $\frac{3(3+x)-6(x-3)-(x-3)^{2} }{(x-3)^{2}*(3+x) } =0$
3. $\frac{-x^{2} +6x-3x+18}{(x-3)^{2}*(3+x)} =0$
4. $\frac{-x*(x-6)-3*(x-6)}{(x-3)^{2} *(3+x)} =0$
5. $\frac{-(x-6)(x+3)}{(x-3)^{2} *(3+x)}=0$
6. $\frac{6-x}{(x-3)^{2} }=0$