Question

абвгд математика памагити

Answer 1

Ответ:

$\frac{4x}{ {x}^{2} + 5x } = \frac{4x}{x(x + 5)} = \frac{4}{x + 5}$

$\frac{9 {y}^{2} - {x}^{2} }{6y + 2x} = \frac{(3y - x)(3y + x)}{2(3y + x)} = \frac{3y - x}{2}$

$\frac{3x - 1}{ {x}^{2} } + \frac{x - 6}{2x} = \frac{6x - 2 + {x}^{2} - 6x }{2 {x}^{2} } = \frac{ {x}^{2} - 2 }{2 {x}^{2} }$

$\frac{5}{c + 2} - \frac{5c - 2}{ {c}^{2} + 2c } = \frac{5}{c + 2 } - \frac{5c - 2}{c(c + 2)} = \frac{5c - 5c + 2}{c(c + 2)} = \frac{2}{c(c + 2)}$

$\frac{x + y}{3 {y}^{2} } \times \frac{y}{x + y} = \frac{1}{3y}$

$\frac{4x}{ {x}^{2} - {y}^{2} } \div \frac{ {x}^{3} }{x - y} = \frac{4x}{(x - y)(x + y)} \times \frac{x - y}{ {x}^{3} } = \frac{4}{ {x}^{2}(x + y) }$

$( \frac{4}{x - 2} + \frac{2x}{x + 2} ) \div \frac{ {x}^{2} + 4 }{ {x}^{2} - 4 } = ( \frac{4x + 8 + 2 {x}^{2} - 4x}{(x - 2)(x + 2)}) \times \frac{(x - 2)(x +2)}{ {x}^{2} + 4 } = \frac{2 {x}^{2} + 8 }{(x - 2)(x + 2)} \times \frac{(x - 2)(x + 2)}{ {x}^{2} + 4} = \frac{2(x + 4)}{ {x}^{2} + 4}$

$\sqrt{48} \times \sqrt{3} \times {(0.6} \sqrt{10} )^{2} = \sqrt{ {4}^{2} \times {3}^{2} } \times {( \frac{3}{5} \sqrt{10} )}^{2} = 12 \times \frac{9}{25} \times 10 = \frac{216}{5} = 43 \frac{1}{5}$