Предмет: Алгебра, автор: watherlo

Нужно построить график функции
(y-3x-4)(x+3y-4)<=0
и объяснить

watherlo: исправил условие

Ответы

Автор ответа: asphyxik
1

Ответ:

Объяснение:

вырази у из каждой скобки

y - 3x - 4 = 0

y = 3x + 4

x + 3y - 4 = 0

3y =  (-x + 4)

y = (- x + 4) / 3

затем изобрази на графике каждую из этих линейных функций

решение неравенства будет все то, что находится под графиками

Приложения:
watherlo: спасибо
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