Question

y-x=2
y^2-2xy-x^2=-28

Answer 1

$left { {{y-x=2} atop {y^2-2xy-x^2=-28}} right. \ \ y=2+x \ (2+x)^2-2x(2+x)-x^2=-28 \ 4+4x+x^2-4x-2x^2-x^2=-28 \ -2x^2+4=-28 \ -2x^2=-32 \ x^2=16 \ x_1 = -4 \ x_2 = 4 \ y_1=2-4=-2 \ y_2=2+4=6$